Frames:

3. Circle not at the origin

Again: What is the locus of points equidistant from a fixed point?

In the previous section we placed the fixed point at the origin. This is of course an assumption — the resulting equation is therefore a special case which only applies in the special case when the fixed point is at the origin. But what if the fixed point is not at the origin?

Open the Moving Circle applet:  

The applet shows the graph of a circle as the locus of all points a distance r from a fixed point M(a, b) and the equation of the circle for specific values of a, b and r.

Move point M (drag it, or click the sliders), and watch the equation change ....
Develop a theory connecting the values of a, b and r, the equation and the graph of the circle.


We use different approaches to find the equation of the circle in the following two activities.

Open the Translated Circle applet below.

In the applet, click the Shift buttons and carefully observe how the coordinates of P, P' and P'' change.

Animate or move points P and (a, b) and observe how the coordinates change.
How can you use this information to deduce the equation of the circle with centre (a, b) and radius r?

  



Use the definition of the distance between two points to find the locus of points that are equidistant from a fixed point.

Click for a discussion:


The standard form of the equation of the circle with centre at point (a, b) and radius r is:




In the applet, animate or drag point A.

Clear traces and then animate point B.

Find the equations generating the two loci.

Click for a discussion:

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